IB Math AA SL · Topic 2
Functions
The topic that every other topic borrows from. A function is a rule with a domain and a range, and most of the course is that rule seen three ways — as an equation, as a graph and as a model. Here the work is knowing which representation answers the question, and writing the features you found in the form the mark scheme asks for.
What the syllabus covers
Eleven assessed sections, SL 2.1 to 2.11 — from straight lines to the transformation of graphs.
How it is examined
Functions questions are rarely about a single skill. They chain two or three, and the marks follow the chain.
Paper 1 (no calculator) solves by hand: factorising, completing the square, the quadratic formula, exact asymptotes, composite and inverse functions with exact values. Paper 2 (technology) hands the intersection or the maximum to the GDC and marks how you set the problem up.
Sketches are marked on features, not on artistry: the intercepts, the asymptotes and the vertex have to be present and labelled with their coordinates or equations, and the shape has to behave near them.
'Find the values of k for which the equation has two distinct real roots' is the discriminant in disguise. It needs Δ > 0, a strict inequality, and a conclusion about k — not just a value of Δ.
Asymptotes are equations. A vertical asymptote is x = −2, not −2; a horizontal one is y = 3, not 3.
Transformations are described in words, one at a time and completely: the type, the direction and the size. 'Moved by 3' is not a description; 'a translation of 3 units to the right' is.
Domain and range are statements about x and y, usually as inequalities, and for an inverse they swap: the range of f becomes the domain of f⁻¹.
A marked question, mark by mark
A discriminant question where the method is right and the condition is not stated — exactly the shape of most lost marks in this topic.
Practise the whole chain, on fresh exercises
From SL 2.1 lines to SL 2.11 transformations, every generated exercise comes back with each mark awarded or withheld and a reason — including the labels and conditions that are easy to forget.
Start your trialNew to the codes? M1, A1, R1 explained →
The discriminant · SL 2.7
Seed 7P14
Consider the equation x² + 6x + k = 0, where k is a constant.
- (a)Find the values of k for which the equation has two distinct real roots, stating the condition you use.
Your work
Δ = 6² − 4(1)(k) = 36 − 4k
Δ ≥ 0, so k ≤ 9
Marks awarded
- M1Mark awarded. Discriminant Δ = b² − 4ac written and evaluated correctly: 36 − 4k.
- A1Mark not awarded. k ≤ 9 includes k = 9, where the roots coincide. 'Two distinct' needs the strict k < 9.
- R1Mark not awarded. The condition for two distinct real roots, Δ > 0, was never stated; Δ ≥ 0 is the condition for real roots.
Where marks are actually lost
The calculation is usually fine. The marks are lost in how the answer is written down.
Giving an asymptote as a number — '−2' — instead of as an equation, x = −2.
CostThe answer mark is for the equation. A number alone does not say whether the asymptote is vertical or horizontal.
Sketching a graph without labelling the intercepts, asymptotes and vertex.
CostSketch marks are awarded for each key feature shown with its coordinates or equation; an unlabelled curve earns the shape and little else.
Composing functions in the wrong order — (f ∘ g)(x) written as g(f(x)).
CostEverything downstream is built on the wrong function. Follow-through can rescue later marks, but the composition mark itself is gone.
Describing a transformation incompletely, or two transformations in one phrase.
CostEach transformation is marked separately on its type, direction and size; a vague description scores none of them.
Other Math AA SL topics
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